P.S. You need to pass an array of pointers, not a pointer to an array of chars. So. The program control is transferred to the calling function after the return statement. In main, char *s is initialized to the string literal "hello".This means s will be pointing to an anonymous array of 6 char containing the values { 'h', 'e', 'l', 'l', o', '\0' }.However, the contents of this array are not modifiable as far as the standard is concerned, so any code that writes to this array exhibits undefined behavior. #include void disp( int *num) { printf("%d ", *num); } int main() { int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0}; for (int i=0; i<10; i++) { /* Passing addresses of array elements*/ disp (&arr[i]); } return 0; } passing char ** to a function that expects const char** : … However, it is not needed to fill the string. Passing array to function in C programming with example char *ptr is the character pointer that will store the base address of the character array (string) which is going to be passed through main () function. Else, we have to declare structure variable as global variable. Example 1. How Arrays are Passed to Functions in C/C++? - GeeksforGeeks There are different ways in which parameter data can be passed into and out of methods and functions. . It means only the address of the structure is passed to another function.
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